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Question

If I=100010001P=100010001. Then the matrix P3+2P2 is equal to

A
P
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B
IP
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C
2I+P
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D
2IP
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Solution

The correct option is C 2I+P
Given,
P=100010001.
Now
P2=100010001 100010001
or, P2= 100010001=I......(1).
Now, P3=P [ From (1) we get]......(2).
Now P3+2P2
=P+2I [Using (1) and (2)]

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