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Potentiometer

If I current ...

Question

If I current is flowing in a potentiometer wire of length $L$ and resistance $R$ , then potential gradient will be

\frac{I R}{L}

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I R L

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\frac{R L}{I}

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\frac{I L}{R}

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Solution

The correct option is A $\frac{I R}{L}$
The potential is the fall of potential per unit length of potentiometer wire, hence
$k = \frac{V}{L}$
$k = \frac{I R}{L}$

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