If I=∫(√cotx−√tanx)dx equals √2log|f(x)+√g(x)|+C, then which of the following is/are correct ?
A
f(x)=sinx+cosx
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B
g(x)=sin2x
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C
g(x)=sinx
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D
f(x)=sinx−cosx
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Solution
The correct option is Bg(x)=sin2x I=∫cosx−sinx√cosxsinxdx
Put sinx+cosx=t, so that 2sinxcosx=t2−1 ∴I=√2∫dt√t2−1=√2log|t+√t2−1|+C =√2log|sinx+cosx+√sin2x|+C