If I drop a ball near the surface of the moon, will it still cover distances in the ratio 1:4:9 every second of its fall?
If I dropped a ball near the surface of the moon, will it still fall in such a way that the ratio of thetotal distances it covers as it falls , after every second, is in the ratio 1:4:9 ?
If instead of dropping, I threw a ball down at some velocity u,near the surface of the earth, the ratio of the distances covered in the 1st , 2nd and 3rd second (not after n seconds) will be ?
I drop a ball from an aeroplane. If there was no air, will the ball still fall at a uniform acceleration ie. in ratios 1:4:9?