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Question

If I=π20dx1+sin3x, then


A

0<I<1

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B

I>π22

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C

I<2π

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D

I>2π

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Solution

The correct option is B

I>π22


Since, x ϵ [0,π2] 11+sin3x2 1211+sin3x1 π2012dxπ20dx1+sin3xπ20dxπ22Iπ2.


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