CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

If In=π40tanndx, then 1I2+I4,1I3+I5,1I4+I6 form

A
an A.P
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
a G.P
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a H.P
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
an AGP
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A an A.P
In=π/40tannx dx
In+2=π/40tannx(tan2x)dx
=π/40tannx(sec2x1)dx
=π/40tannx d(tanx)In
In+2+In=1n+1
I2+I4=13
I3+I5=14
I4+I6=15
So,1I2+I4;1I3+I5;1I4+I6 forms an AP

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon