If In=∫(ln x)n dxthenIn+nIn−1
(ln x)nx
x (ln x)n−1
x (ln x)n
None of these
In=x(ln x)n−∫x(n)(ln x)n−1xdx =x(ln x)n−nI(n−1) ⇒In+nIn−1=x(ln x)n