If I place a dielectric of thickness 2cm and relative permittivity 2 in between the plates of a parallel plate capacitor, with area 3cm2 and plate spacing 4 cm, what is the new capacitance?
A
2ε0×10−2F
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B
ε0×10−2F
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C
3ε0×10−2F
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D
None of these.
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Solution
The correct option is Bε0×10−2F When a dielectric of thickness t is introduced, the capacitance changes to C=ε0Ad−t+tk If you don’t know where this formula comes from, go back to the videos where this is derived. Now, C=ε0×3×10−4(4−2+22)×10−2 C=ε0×10−2F