If i -1- then 1- i 2- i 3- i 6- i 8 is equal toA- 2- iB- 1C- 3D- -1

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if i =√-1, th...

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if i = $\sqrt{- 1}$ , then $1 + i^{2} + i^{3} + i^{6} + i^{8}$ is equal to

2-i

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-1

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\sqrt{- 1}, t h e n 1 + i^{2} + i^{3} - i^{6} + i^{8}

i^{2} = - 1

1 + i^{2} + i^{4} + i^{6} + i^{8} + . . . . . . . . . . . . . t o (2 n + 1)

If $i^{2} = - 1$ , then the sum $i + i^{2} + i^{3} + . . . . . .$ upto 1000 terms is equal to

i^{2} = - 1

1 + i^{2} + i^{4} + i^{6} + i^{8} + . . .

\frac{i^{592} + i^{590} + i^{588} + i^{586} + i^{584}}{i^{582} + i^{580} + i^{578} + i^{576} + i^{574}}

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