If I take a 2 digit number and add to it the number formed by swapping the digits, the resultant number is surely divisible by

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Solution

The correct option is D 11
Let the original number = ab.
ab = 10a +b
Now, the number formed by swapping the digits = ba = 10b + a
Their sum will be equal to:
(10a + b) + (10b + a) = 11a + 11b
= 11 (a + b)
$\Rightarrow$ Their sum will be surely divisible by 11.

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If I take a 2 digit number and add to it the number formed by swapping the digits, the resultant number is surely divisible by

The correct option is D 11Let the original number = ab. ab = 10a +b Now, the number formed by swapping the digits = ba = 10b + a Their sum will be equal to: (10a + b) + (10b + a) = 11a + 11b = 11 (a + b) ⇒ Their sum will be surely divisible by 11.

The correct option is D 11
Let the original number = ab.
ab = 10a +b
Now, the number formed by swapping the digits = ba = 10b + a
Their sum will be equal to:
(10a + b) + (10b + a) = 11a + 11b
= 11 (a + b)
$\Rightarrow$ Their sum will be surely divisible by 11.