If $I . V .$ of rating of $2000$ watt is operated for $5$ hrs per day. Find the number of units consumed in leap year?

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Solution

Energy consumed is given as

$E = P \times t$

By substituting the values in the above equation we get the energy

$E = 2000 \times 5$

$E = 10000$

The energy consumed in 366 days is

$366 \times 10^{4}$

Hence the total energy consumed in a leap year $366 \times 10^{4}$

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If I.V. of rating of 2000 watt is operated for 5 hrs per day. Find the number of units consumed in leap year?

Energy consumed is given as E=P×t By substituting the values in the above equation we get the energy E=2000×5 E=10000 The energy consumed in 366 days is 366×104 Hence the total energy consumed in a leap year366×104

If $I . V .$ of rating of $2000$ watt is operated for $5$ hrs per day. Find the number of units consumed in leap year?

Energy consumed is given as

$E = P \times t$

By substituting the values in the above equation we get the energy

$E = 2000 \times 5$

$E = 10000$

The energy consumed in 366 days is

$366 \times 10^{4}$

Hence the total energy consumed in a leap year $366 \times 10^{4}$