If I - x - I -1- Find - x - where I is an integrA- I-1B- -IC- -I-1D- - I -1

The correct option is C I 1 [x] is the greatest integer function If I lt; x lt; I +1 means x is between I and I +1. ⇒ I 1 lt; x lt; I, x will ...

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Squaring an Inequality

If I < x < I ...

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If I < x < I +1, Find [-x], where I is an integr

-I

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-I+1

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-I-1

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I-1

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If I < x < I +1, Find [-x], where I is an integr

If I < x < I +1 , find [-x] where I is an integer.

I = \int_{0}^{1} e^{x^{2}} d x

(a) I < 1 (b) I \leq 0

(c) I > 1 (d) I \leq 1

\hat{i}, \hat{j}, \hat{k}

\hat{i} \cdot \hat{j} = 1

\hat{i} \cdot \hat{i} = 1

\hat{i} \times \hat{j} = 1

\hat{i} \times (\hat{j} \times \hat{k}) = 1

If $\frac{(1 + i) x - 2 i}{3 + i} + \frac{(2 - 3 i) y + i}{3 - i} = i$ , then the real values of x and y are given by :

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