If I lt- x lt- I -1- Find -x- where I is an integr- -I-I-1-I-1-I-1-

The correct option is C I 1 [x] is the greatest integer function If I lt; x lt; I +1 means x is between I and I +1. ⇒ I 1 lt; x lt; I, x will ...

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Standard VIII

Mathematics

Greatest integer function

If I lt; x...

Question

If I < x < I +1, Find [-x], where I is an integr

-I

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-I+1

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-I-1

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I-1

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Solution

The correct option is C
-I-1

[x] is the greatest integer function
If I < x < I +1 means x is between I and I +1.
$\Rightarrow$ -I -1 < -x < -I, -x will lie between (-I-1) and -I
$\Rightarrow$ [-x] = -I - 1

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Similar questions

Q. Find the real values of x and y, if
(i)

(x + i y) (2 - 3 i) = 4 + i

(ii)

(3 x - 2 i y) (2 + i)^{2} = 10 (1 + i)

(iii)

\frac{(1 + i) x - 2 i}{3 + i} + \frac{(2 - 3 i) y + i}{3 - i}

(iv)

(1 + i) (x + i y) = 2 - 5 i

Find the real values of x and y, if

$(i) (x + i y) (2 - 3 i) = 4 + i (i i) (3 x - 2 i y) (2 + i)^{2} = 10 (1 + i) (i i i) \frac{(1 + i) x - 2 i}{3 + i} + \frac{(2 - 3 i) y + i}{3 - i} = i (i v) (1 + i) (x + i y) = 2 - 5 i$

$If {(\frac{1 + i}{1 - i})}^{3} - {(\frac{1 - i}{1 + i})}^{3} = x + i y, find (x,y)$

If I < x < I +1, Find [-x], where I is an integr

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If I < x < I +1, Find [-x], where I is an integr

The correct option is C -I-1 [x] is the greatest integer function If I < x < I +1 means x is between I and I +1. ⇒ -I -1 < -x < -I, -x will lie between (-I-1) and -I ⇒ [-x] = -I - 1

The correct option is C
-I-1

[x] is the greatest integer function
If I < x < I +1 means x is between I and I +1.
$\Rightarrow$ -I -1 < -x < -I, -x will lie between (-I-1) and -I
$\Rightarrow$ [-x] = -I - 1