If identity 4 proofs that (a+b)(a+c)=(a*a)+[(b+c)a]+BC then what will be (a+b)(a-b) equal to ?

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Solution

Put c=-b in (a+b)(a+c)

(a+b)(a-b)=(a×a)+[(b-b)a]+b×-b
=a²-b²

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