If if the distance travelled by the body in the nth second is given by (4 + 6n) then find the initial velocity and acceleration of the body
Snth = u + a(n-1/2)
= u -a/2 + an
Snt = 4 + 6n (given)
comparing both equations
u-a/2 = 4 , a = 6m/s2
u = 4+a/2 = 7m/s
approve my ans if u like it...thanks good luck :)