If impulse $I$ varies with time $t$ as $f (k g m s^{- 1}) = 20 t^{2} - 40 t$ . The change in momentum is minimum at

t = 1 s

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t = 2 s

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t = \frac{1}{2} s

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t = \frac{3}{2} s

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Solution

The correct option is A $t = 1 s$
The definition of impulse, $I = F d t = m \frac{d v}{d t} d t = m d v =$ change in momentum.
Thus, $I = 20 t^{2} - 40 t$
For minimum of impulse, $\frac{d I}{d t} = 0$
or $40 t - 40 = 0$ or $t = 1 s$

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If impulse I varies with time t as f(kgms−1)=20t2−40t. The change in momentum is minimum at

The correct option is A t=1sThe definition of impulse, I=Fdt=mdvdtdt=mdv= change in momentum.Thus, I=20t2−40tFor minimum of impulse, dIdt=0or 40t−40=0 or t=1s

If impulse $I$ varies with time $t$ as $f (k g m s^{- 1}) = 20 t^{2} - 40 t$ . The change in momentum is minimum at

The correct option is A $t = 1 s$
The definition of impulse, $I = F d t = m \frac{d v}{d t} d t = m d v =$ change in momentum.
Thus, $I = 20 t^{2} - 40 t$
For minimum of impulse, $\frac{d I}{d t} = 0$
or $40 t - 40 = 0$ or $t = 1 s$