If in a A-P- the third term is 3- the sixth term is 5 and nth term is 203-3- then the value of n is

Given : T_3 = 3, T_6= 5, T_n = 2033 a+2d= 3 a+5d = 5 ⇒ d = 23⇒ a = 5 3 T_n = 2033 ⇒ a+(n 1)× d= 2033 ⇒ 5 3+(n 1)×23 = 2033 ⇒ 5+(n 1)× 2 = 203 ∴ n = 100 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Series

If in a A.P. ...

Question

If in a A.P. the third term is $3$ , the sixth term is $5$ and $n^{t h}$ term is $\frac{203}{3}$ , then the value of $n$ is

Open in App

Solution

Given : $T_{3} = 3, T_{6} = 5, T_{n} = \frac{203}{3}$
$a + 2 d = 3 a + 5 d = 5 \Rightarrow d = \frac{2}{3} \Rightarrow a = \frac{5}{3} T_{n} = \frac{203}{3} \Rightarrow a + (n - 1) \times d = \frac{203}{3} \Rightarrow \frac{5}{3} + (n - 1) \times \frac{2}{3} = \frac{203}{3} \Rightarrow 5 + (n - 1) \times 2 = 203 ∴ n = 100$

Suggest Corrections

Similar questions

Q. If in a A.P. the third term is

3

, the sixth term is

5

and

n^{t h}

term is

\frac{203}{3}

, then the value of

n

Q. In a

G . P

., if third term is

63

and the sixth term is

1701

, find its

n^{t h}

term.

If the sum of n terms of an A.P is $2 n^{2} + 3 n$ , then write its nth term.

Find the first term of an A.P whose common difference is

- 3

and

n = 18

n^{t h}

term is

- 5

Q. If the

n^{t h}

term of an A.P. is

t_{n} = 3 - 5 n

, then the sum of the first

n

terms is :

Join BYJU'S Learning Program

If in a A.P. the third term is 3, the sixth term is 5 and nth term is 2033, then the value of n is

Given : T3=3, T6=5, Tn=2033 a+2d=3a+5d=5⇒d=23⇒a=53Tn=2033⇒a+(n−1)×d=2033⇒53+(n−1)×23=2033⇒5+(n−1)×2=203∴n=100

If in a A.P. the third term is $3$ , the sixth term is $5$ and $n^{t h}$ term is $\frac{203}{3}$ , then the value of $n$ is