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Standard IX
Chemistry
Ionic Compounds: Chemical Formula
If in a mixed...
Question
If in a mixed oxide of elements A and B, the oxide ions are arranged in CCP lattice and cations (A2+) occupy 12.5% of tetrahedral voids and cation (B3+) occupy 50% octahedral voids, the formula of the oxide is
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Q.
In a closed packed structure of mixed oxides, the lattice is composed of mixed oxides ions. One-eighth of tetrahedral voids are occupied by divalent cations
(
A
2
+
)
while one half of octahedral voids are occupied by trivalent cations
(
B
3
+
)
. The formula of mixed oxide is :
Q.
In a solid, oxide ions
(
O
2
−
)
are arranged in ccp, cation
(
A
3
+
)
occupy one-sixth of tetrahedral void and cations
(
B
3
+
)
occupy one-third of the octahedral voids. What is the formula of the compound?
Q.
In a compound
A
B
6
O
4
,
oxide ions are arranged in ccp and cations A are present in octahedral voids. Cations B are equally distributed among octahedral and tetrahedral voids. The fraction of the octahedral voids occupied is :
Q.
In a compound, oxides ions form fcc lattice, whereas
1
4
t
h
of tetrahedral voids are occupied by cations
A
2
+
and
1
8
t
h
of octahedral voids are occupied by cations
B
3
+
ions. The simplest formula of the compound is
Q.
In a close-packed structure of mixed oxides, the lattice is composed of oxide ions, one-eighth of tetrahedral voids are occupied by divalent cations
A
while one-half of octahedral voids are occupied by trivalent cations
B
. The formula of the oxide is:
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