Question

If in a moderately asymmetrical distribution mean and mode are $9a$ and $6a$ respectively then median of the distribution is...............

• A. $6a$
• B. $9a$
• C. $8a$
• D. $15a$

Answer 1

Answer: (C)

$8a$

According to the given data, $\text{mean}=9a,\text{mode}=6a$

Use the relationship between mean, median and mode.

$\text{mode}=3\text{median}-2\text{mean}$

$\therefore \text{median}=\frac{\text{mode}+2\text{mean}}{3}=\frac{6a+(2\times 9a)}{3}$

$=8a$