If in a nuclear fusion process the masses of the fusing nuclei be $m_{1}$ and $m_{2}$ and the mass of the resultant nucleus be $m_{3}$ , then:

m_{3} = | m_{1} - m_{2} |

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m_{3} < (m_{1} + m_{2})

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m_{3} > (m_{1} + m_{2})

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m_{3} = m_{1} + m 2

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Solution

The correct option is C $m_{3} < (m_{1} + m_{2})$
In nuclear fusion, the mass of end product/resultant is always less than the sum of the initial product, the rest is liberated in the form of energy like in sun, energy is liberated due to the fusion of $2$ hydrogen atoms.

$m_{3} < (m_{1} + m_{2})$

where $m_{3} =$ mass of the end product

$m_{1}$ & $m_{2} =$ the mass of the initial two products

$∴$ Correct answer is option B.

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If in a nuclear fusion process the masses of the fusing nuclei be m1 and m2 and the mass of the resultant nucleus be m3, then:

If in a nuclear fusion process the masses of the fusing nuclei be $m_{1}$ and $m_{2}$ and the mass of the resultant nucleus be $m_{3}$ , then: