If in a number , difference between the sum of digits at its odd places and that of digits at the even places is given 0, then the number is divisible by _____ .
A
7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
11
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D11 Divisibility Test for 11 :
→Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number.
So, for instance, 2728 has alternating sum of digits 2−7+2−8=−11
Since, −11 is Divisible by 11, So is 2728.
Here,
Given that Difference between Sum of digits at Odd places and that of Digits at even places is 0.
Hence, By Divisibility Test of 11, Number is Divisible by 11.