Question

# If in a photoelectric cell, the wavelength of incident light is changed from 4000˚A to 3600˚A, then the change in stopping potential will be

A
0.34 volt
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B
0.57 volt
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C
0.71 volt
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D
0.23 volt
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Solution

## The correct option is A 0.34 voltThe maximum kinetic energy of photoelectrons in eV isEmax=hν−ϕwhere,ν is the frequency of incident light and ϕ is photoelectric work function of metal.Emax=eVswhere, Vs is stopping potential and e is electronic chargeeVs=(hν−ϕ)eVeVs=(hcλ−ϕ)eVFor the wavelength of incident light 4000A∘eV1=(hc4000−ϕ)eV eV1=(123754000−ϕ)eV When the wavelength of incident light changes to 3600A∘eV2=(hc3600−ϕ)eV eV2=(123753600−ϕ)eV thereforeeV1−eV2=(123754000−ϕe−123753600+ϕe)eVe(V1−V2)=(3.09−3.43)eV=0.34eVV1−V2=0.34VSo, the answer is option (A).

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