If in a poisson distribution P(X=1)=P(X=2); the mean of the distribution f(x)=e−xλx∠x is
A
1
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B
2
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C
12
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D
32
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Solution
The correct option is B2 Poisson's distribution implies P(X=n)=λne−λn! Where mean=variance=λ Hence P(x=1)=P(x=2) λ1e−λ1!=λ2e−λ2! λ=2 Hence mean=variance=2