If in a quadrilateral ABCD, AB=BC and CD=DA and AB not equal to CD, then the figure formed would be a kite.

True

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False

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Solution

The correct option is A
True

The figure will be a kite. The very definition of kite in geometry is a quadrilateral with two disjoint pairs of adjacent sides equal.

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Similar questions

If in a quadrilateral $A B C D$ , $A B = B C$ and $C D = D A$ , then the figure is a kite.

Let ABCD be a quadrilateral with diagonals AC and BD. Prove the following statements (Compare these with the previous problem);

(a) AB + BC + CD > AD;

(b) AB + BC + CD + DA > 2AC;

(d) AB + BC + CD + DA > AC + BD.

=

=

A B C D

A B | | C D

C D ⊥ D A

A B = 16 c m, D C = B C = 10 c m

A B C D

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