If in a random experiment, the total number of outcomes are 'n' of which 'm' are favourable for an event E , then P(E) = __________.

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\frac{m}{n}

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\frac{n}{m}

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Solution

The correct option is C $\frac{m}{n}$
If in a random experiment, the total number of outcomes are 'n' of which 'm' are favourable for an event E , then P(E) is the probability of the event E and is defined as
P(E) = $\frac{f a v o u a b l e o u t c o m e s}{t o t a l o u t c o m e s}$ = $\frac{m}{n}$

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Which of the following options correctly explains the relationship between m and n?

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Which of the following options correctly explains the relationship between m and n?

Q. We know that Probability of an event E, written as
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= \frac{N u m b e r o f o u t c o m e s f a v o u r a b l e t o E (m)}{N u m b e r o f a l l p o s s i b l e o u t c o m e s o f t h e e x p e r i m e n t (n)}

.

Which of the following options correctly explains the relationship between m and n?

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If in a random experiment, the total number of outcomes are 'n' of which 'm' are favourable for an event E , then P(E) = __________.

The correct option is C mnIf in a random experiment, the total number of outcomes are 'n' of which 'm' are favourable for an event E , then P(E) is the probability of the event E and is defined as P(E) = favouable outcomestotal outcomes = mn