If in a right-angled triangle 'h' is the hypotenuse, 'a' and 'b' are the perpendicular sides, then .
A
h=a+b
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B
h2=a2+b2
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C
h=a-b
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D
h2=a2−b2
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Solution
The correct option is Bh2=a2+b2 Pythagoras Theorem states that in a right-angled triangle, the sum of the square of the sides containing the right angle is equal to the square of the hypotenuse. Thus, h2=a2+b2