If in a right triangle, the hypotenuse is 20 m and the difference between the lengths of other sides is 4 m. Then, the sides are 14 and 18.

False

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

True

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
False

Let other two sides of right triangle be x and x + 4, then
$x^{2} + (x + 4)^{2} = 20^{2}$
$2 x^{2} + 8 x + 16 = 400$
$2 x^{2} + 8 x - 384 = 0$
$x^{2} + 4 x - 192 = 0$
Solving this equation, we get
$x$ = 12 or – 16
Let's consider only positive value for length
The two sides are 12 m and 12 + 4 or 16 m.

Suggest Corrections

Similar questions

The hypotenuse of a right-angled triangle is 20 m. If the difference between the lengths of the other two sides is 4 m., find the length of the sides.

Q. In a right-angled triangle the hypotenuse is of

13

cm and the difference between the other sides is

7

cm, then find the two sides.

Q. The hypotenuse of a right triangle is 25 cm. The difference between the lengths of the other two sides of the triangle is 5 cm. The product of the lengths of these sides is __ cm.

Q. In a right angled triangle the length of hypotenuse is

15

and the difference between the other sides is

3

, then find the length of the sides.

The measure of one side of a right triangle is 4.2m. If the difference of the lengths of hypotenuse and other is 14m, find the sides and area of the triangle.

Join BYJU'S Learning Program

If in a right triangle, the hypotenuse is 20 m and the difference between the lengths of other sides is 4 m. Then, the sides are 14 and 18.

The correct option is A False Let other two sides of right triangle be x and x + 4, then x2+(x+4)2=202 2x2+8x+16=400 2x2+8x−384=0 x2+4x−192=0 Solving this equation, we get x = 12 or – 16 Let's consider only positive value for length The two sides are 12 m and 12 + 4 or 16 m.