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Question

If in a series tn=n+1(n+2)! then 10n=0tn is equal to?

A
1110!
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B
1111!
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C
1112!
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D
None of these
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Solution

The correct option is C 1112!
Solution - It is given that tn=n+1(n+2)!tn=n+1+11(n+2)!=(n+2)1(n+2)! th =n+2(n+2)!1(n+2)!

tn=1(n+1)!1(n+2)! 10n=0tn=10n=0(1(n+1)!1(n+2)!)


=11(12!+12!13!+13!14!111!+111!)112!=1112! Hence, (C) is the correct option.

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