If in a stationary lift a man is standing, with a bucket full of water having a hole at its bottom. The rate of flow of water through this hole is $R_{0}$ . If the lifts starts to move up and down with same acceleration and rates of flow of water are $R_{u}$ and $R_{d}$ , then

R_{o} > R_{u} > R_{d}

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R_{u} > R_{o} > R_{d}

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R_{d} > R_{o} > R_{u}

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R_{u} > R_{d} > R_{o}

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Solution

The correct option is B $R_{u} > R_{o} > R_{d}$
Rate of flow will be more when lift will move in upward
direction with some acceleration because the net downward the pull will be more and vice-versa.
$F_{u p w a r d} = m (g + a)$ and $F_{d o w n w a r d} = m (g - a)$

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