If in a stationary wave the amplitude corresponding to anti node is 4 cm, then the amplitude corresponding to a particle of medium located exactly between a node and an anti node is

2 c m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 \sqrt{2} c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{2} c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.5 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $2 c m$
A node has a zero amplitude and anti-node has the maximum amplitude. So, the amplitude at anti-node is $4 c m$ . The exact between a node and anti-node is $2 c m$ .
The correct option is A.

Suggest Corrections

Similar questions

4 cm

4 cm

Y = 4 s i n (\begin{matrix} \frac{π x}{15} \end{matrix}) c o s (96 π t)

6

Join BYJU'S Learning Program