If in a stationary wave the amplitude corresponding to antinode is 4cm, then the amplitude corresponding to a particle of medium located exactly midway between a node and an antinode is
A
2cm
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B
2√2cm
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C
√2cm
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D
1.5cm
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Solution
The correct option is B2√2cm Equation of a stationary wave is given by y=A0sin(kx)cos(ωt)....(1)
Mid way between a node and antinode is λ8 from the origin.
From (1), Function for amplitude is A=A0sin(kx) A=4sin(2πλ×λ8) A=2√2cm