Question

If in a transformer the number of turns of primary coil and secondary coil are $5$ and $4$ respectively and $240$ V is applied to primary coil, then the ratio of current in primary and secondary coil is :

• A. $4:5$
• B. $5:4$
• C. $5:10$
• D. $8:12$

Answer 1

Answer: (A)

$4:5$

$\frac{N_P}{N_S}=\frac{5}{4},V_P=240V$

$\frac{N_P}{N_S}=\frac{V_P}{V_S}=\frac{I_S}{I_P}$

$\therefore \frac{5}{4}=\frac{I_S}{I_P}$ (or) $I_P:I_S=4:5$