If in a triangle A - 1-10 - circumference - - 1 - 3 - 2 - 3 and orthocentre - 11 - 3 - 4 - 3 then the co-ordinate of mid-point of side opposite to A is

The correct option is D ( 1 , 11 / 3 ) ...

You visited us 72 times! Enjoying our articles? Unlock Full Access!

Geometrical Representation of a Complex Number

If in a trian...

Question

If in a triangle $A = (1, 10),$ circumference $= (- \frac{1}{3}, \frac{2}{3})$ and orthocentre $= (\frac{11}{3}, \frac{4}{3})$ then the co-ordinate of mid-point of side opposite to $A$ is

(1, 6)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(1, 5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(1, - 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(1, - \frac{11}{3})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

A = (1, 10),

= (- \frac{1}{3}, \frac{2}{3})

= (\frac{11}{3}, \frac{4}{3})

A

A B C, A \equiv (1, 10)

\equiv (- \frac{1}{3}, \frac{2}{3})

\equiv (\frac{11}{3}, \frac{4}{3})

A

A B C, A = (1, 10)

= (- \frac{1}{3}, \frac{2}{3})

= (\frac{11}{3}, \frac{4}{3})

A

Δ A B C, A \equiv (1, 10),

\equiv (- \frac{1}{3}, \frac{2}{3})

\equiv (\frac{11}{3}, \frac{4}{3}),

B C

\equiv (1, 10)

\equiv

(\frac{- 1}{3}, \frac{2}{3})

\equiv

(\frac{11}{3}, \frac{4}{3})

Join BYJU'S Learning Program