if in a $△ A B C$ , $cos 3 A + cos 3 B + cos 3 C = 1$ , then one angle must be exactly equal to

60^{o}

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90^{o}

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120^{o}

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150^{o}

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Solution

The correct option is C $120^{o}$
answer is C

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Similar questions

△ A B C, cos 3 A + cos 3 B + cos 3 C = 1

In a triangle ABC , cos 3A+ cos 3B+ cos 3C = 1 ,then find any one angle.

cos 3 A + cos 3 B + cos 3 C = 1

△ A B C, {cos}^{3} A + {cos}^{3} B + {cos}^{3} C = 3 cos A cos B cos C

cos A + cos B + cos C = 0

cos 3 A + cos 3 B + cos 3 C

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