If in a triangle $A B C$ , if $R r (sin A + sin B + sin C)$ $=$ $96$
then the square of the area of the triangle is?

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Solution

Given $R r (sin A + sin B + sin C) = 96$
$\frac{r}{2} (2 R sin A + 2 R sin B + 2 R sin C) = 96$
$\frac{Δ}{2 s} (a + b + c) = 96$ ( $∵ r = \frac{Δ}{s}$ )
$\Rightarrow Δ = 96$
$\Rightarrow (Δ)^{2} = 9216$ sq.units

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