If in a triangle ABC, (s-a)(s-b) = s(s-c), then angle C is equal to [MP PET 1986]

90^{o}

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45^{o}

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30^{o}

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60^{o}

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Solution

The correct option is A $90^{o}$
$t a n \frac{C}{2} = \sqrt{\frac{(s - a) (s - b}{s (s - c)}} = 1 = t a n (\frac{π}{4}),$ from data. Hence C = $90^{o}$

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