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Question

If in a triangle ABC, the line joining the circumcentre and incentre is parallel to BC, then cosB+cosC is equal to

A
0
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B
1
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C
2
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D
none of these
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Solution

The correct option is A 1
In OBL,cosA=OLOB=rR
RcosA=rRcosA=4RsinA2sinB2sinC2cosA=4sinA2sinB2sinC2cosA=cosA+cosB+cosC10=cosB+cosC1cosB+cosC=1

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