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Byju's Answer
Standard VII
Mathematics
Rotational Symmetry
If in a trian...
Question
If in a triangle
r
r
1
=
r
2
r
3
,
where
r
,
r
1
,
r
2
,
r
3
have their usual meaning, then
A
A
=
90
0
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B
B
=
90
0
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C
C
=
90
0
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D
None of these
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Solution
The correct option is
C
C
=
90
0
Given
r
r
1
=
r
2
r
3
⇒
Δ
(
s
−
a
)
s
Δ
=
Δ
(
s
−
c
)
(
s
−
b
)
Δ
⇒
(
s
−
a
)
(
s
−
b
)
=
s
(
s
−
c
)
⇒
a
b
=
s
(
a
+
b
+
c
)
⇒
a
2
+
b
2
=
c
2
⇒
the triangle is right angled at
C
.
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0
Similar questions
Q.
Assertion :In a
△
A
B
C
, if
a
<
b
<
c
and
r
is inradius and
r
1
,
r
2
,
r
3
are the axradii opposite to angle
A
,
B
,
C
respectively, then
r
<
r
1
<
r
2
<
r
3
Reason:
△
A
B
C
,
r
1
r
2
+
r
2
r
3
+
r
3
r
1
=
r
1
r
2
r
3
r
Q.
Prove that :
a
(
r
r
1
+
r
2
r
3
)
=
b
(
r
r
2
+
r
3
r
1
)
=
c
(
r
r
3
+
r
1
r
2
)
where
r
is inradius and
r
1
,
r
2
,
r
3
are exradius of triangle
A
B
C
and
a
,
b
,
c
are the corresponding sides.
Q.
For
Δ
A
B
C
,
Δ
,
R
,
r
,
r
1
,
r
2
,
r
3
,
s
have the usual meanings, then if the cubic equation with roots
r
1
,
r
2
,
r
3
is
x
3
+
l
x
2
+
m
x
+
n
=
0
, then
l
=
Q.
If
r
1
,
r
2
,
r
3
are the radii of the escribed circles of a triangle
A
B
C
and if
r
is the radius of its incircle,then
r
1
r
2
r
3
−
r
(
r
1
r
2
+
r
2
r
3
+
r
3
r
1
)
is equal to
Q.
Assertion :In a
Δ
ABC,
r
1
+
r
2
+
r
3
−
r
=
4
R
Reason:
r
1
r
2
+
r
2
r
3
+
r
3
r
1
=
Δ
2
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