If in a wire of Young's modulus Y, longitudinal strain X is produced, then the elastic potential energy stored in its unit volume will be
A
0.5YX2
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B
0.5Y2X
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C
2YX2
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D
YX2
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Solution
The correct option is A0.5YX2 Elastic Potential energy per unit volume is given by U=12×stress×strain U=12×Y×(strain)2 (∵stress=Y×strain) ∴U=12X2Y ⇒U=0.5X2Y