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Question

If in ∆ABC and ∆PQR, we have: ABQR=BCPR=CAPQ, then
(a) ∆PQR ∼ ∆CAB
(b) ∆PQR ∼ ∆ABC
(c) ∆CBA ∼ ∆PQR
(d) ∆BCA ∼ ∆PQR

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Solution

(a) ∆PQR ∼ ∆CAB

In ∆ABC and ∆PQR, we have:
ABQR = BCPR = CAPQ ABC~QRPWe can also write it as PQR~CAB.

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