Question

If in an A.C.L - C series circuit, $X_L>X_C$. Hence current .......

• A. lags behind the voltage by $\frac{\pi }{2}$ in phase
• B. leads the voltage by $\frac{\pi }{2}$ in phase
• C. leads the voltage by $\pi$ in phase
• D. lags behind the voltage by $\pi$ in phase

Answer 1

Answer: (A)

lags behind the voltage by $\frac{\pi }{2}$ in phase

$\because X_L>X_C$

$\therefore$ circuit is inductive

$\therefore$ voltage leads.

$\therefore$ current lags behind voltage by $I{I}_2$ in phase.