If in an A.P., the pth term is q and (p + q)th term is zero, then the qth term is
p
As, ap=q
⇒a+(p−1)d=q……(i)
Also, a(p+q)=0
⇒a+(p+q−1)d=0……(ii)
Subtracting (i) from (ii), we get
a + (p + q - 1)d - a - (p - 1)d = 0 - q
⇒(p+q−1−p+1)d=−q
⇒qd=−q
⇒d=−qq
⇒d=−1
Substituting d = - 1 in (i) we get
a+(p−1)×(−1)=q
⇒a−p+1=q
⇒a=p+q−1
Now,
⇒aq=a+(q−1)d
=p+q−1+(q−1)×(−1)
=p+q−1−q+1
=p
Hence, the correct alternative is option (b).