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Question

If in an equilateral triangle ABC, AD is perpendicular to BC, then AD2=


A

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B

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C

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D

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Solution

The correct option is C


In ΔABC, ADBC.

then, AC2=AD2+CD2 [By Pythagorus Theorem]

AD2=AC2CD2

AD2=BC2CD2 [since, AC=BC]

AD2=(2CD)2CD2 [since, BC=2CD]

AD2=3CD2


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