If in an infinite G.P., first term is equal to 10 times the sum of all successive terms, then is common ratio is
111
(b) 111
Let the first term of the G.P. be a
Let its common ratio be r
According to the question, we have :
First term = 10 [Sum of all successive terms]
a=10(ar1−r)
⇒a−ar=10ar
⇒11ar=a
⇒r=a11a=111