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Integration of Piecewise Continuous Functions

If in case |x...

Question

If in case |x+2| =3 , then x+2 = + or - 3

Then why in inequality |x| ≥ 4 , + or - x ≥ 4 and why not x≥ + or - 4 ?

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Solution

because in first case u can also write + or - (x+2) = 3 ie is same as (x+2) = + or - 3

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