If, in defining the specific heat, temperature is represented in $^{o} F$ instead of $^{o} C$ then the numerical value of specific heat will

be converted to heat capacity

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remain unchanged

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decrease

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increase

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Solution

The correct option is C decrease
In defining specific heat,
C = $\frac{Q}{m Δ T}$

F = $\frac{9 C}{5} + 32$
$Δ F > Δ C$
Now, the change in temperature in Fahrenheit scale is greater than that in Celcius scale.
Thus, the specific heat on Fahrenheit scale will decrease numerically.

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If, in defining the specific heat, temperature is represented in oF instead of oC then the numerical value of specific heat will

The correct option is C decreaseIn defining specific heat,C = QmΔTF = 9C5+32ΔF>ΔCNow, the change in temperature in Fahrenheit scale is greater than that in Celcius scale.Thus, the specific heat on Fahrenheit scale will decrease numerically.

If, in defining the specific heat, temperature is represented in $^{o} F$ instead of $^{o} C$ then the numerical value of specific heat will

The correct option is C decrease
In defining specific heat,
C = $\frac{Q}{m Δ T}$

F = $\frac{9 C}{5} + 32$
$Δ F > Δ C$
Now, the change in temperature in Fahrenheit scale is greater than that in Celcius scale.
Thus, the specific heat on Fahrenheit scale will decrease numerically.