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Question

If in ΔABC,A=sin1(x),B=sin1(y)and C=sin1(z), then x1y21z2+y1x21z2+z1x21y2 is :

A
equal to xyz
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B
>1
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C
equal to x2yz
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D
none of these
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Solution

The correct option is A equal to xyz
The above equation reduces to
sinAcosBcosC+sinBcosAcosC+sinCcosAcosB

=cosC(sinAcosB+cosAsinB)+sinCcosAcosB

=cosC[sin(A+B)]+sinCcosAcosB

=cosC[sin(πC)]+sinCcosAcosB

=cosCsinC+sinCcosAcosB

=sinC[cosC+cosAcosB]

=sinC[cosC+12(cos(A+B)+cos(AB))]

=sinC[cosC+12(cos(πC)+cos(AB))]

=sinC[cosC+12cos(C)+12cos(AB)]

=sinC[12cos(C)+12cos(AB)]

=sinC[12cos(AB)12cos(A+B)]

=sinAsinBsinC

=xyz

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