CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If in ΔABC,A=sin1(x),B=sin1(y)and C=sin1(z), then x1y21z2+y1x21z2+z1x21y2 is :

A
equal to xyz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
>1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
equal to x2yz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A equal to xyz
The above equation reduces to
sinAcosBcosC+sinBcosAcosC+sinCcosAcosB

=cosC(sinAcosB+cosAsinB)+sinCcosAcosB

=cosC[sin(A+B)]+sinCcosAcosB

=cosC[sin(πC)]+sinCcosAcosB

=cosCsinC+sinCcosAcosB

=sinC[cosC+cosAcosB]

=sinC[cosC+12(cos(A+B)+cos(AB))]

=sinC[cosC+12(cos(πC)+cos(AB))]

=sinC[cosC+12cos(C)+12cos(AB)]

=sinC[12cos(C)+12cos(AB)]

=sinC[12cos(AB)12cos(A+B)]

=sinAsinBsinC

=xyz

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Triangle Properties
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon