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Question

If, in ΔABC, r3=r1+r2+r, then A+B=

A
120
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B
60
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C
90
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D
45
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Solution

The correct option is C 90
Given, r3=r1+r2+r,
r1+r2=r3r
Δ(sa)+Δ(sb)=Δ(sc)Δs
Δ(2sab(sa)(sb))=Δ(cs(sc))
c(sa)(sb)=cs(sc)
s2cs=s2bsas+ab
s(a+bc)=ab
(a+b+c)(a+bc)=2ab
(a+b)2c2=2ab
a2+b2=c2
C=90
A+B=90

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