If in isothermal process - w work is done by gas-then choose incorrect

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Standard XII

Physics

Thermodynamic Processes

If in isother...

Question

If in isothermal process $Δ$ w work is done by gas,then choose incorrect

Δ U = 0

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Δ S \neq 0

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Δ T = 0

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Δ P = 0

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Solution

The correct option is D $Δ P = 0$
In isothermal process, $Δ T = 0$ ( Temperature change is zero) and internal energy $U = 0$ ,since it is a function of temperature.
$Δ S = \frac{Δ Q}{T} \Rightarrow Δ S \neq 0$

Hence, $D$ is the incorrect option. i.e. $Δ P = 0$

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Similar questions

Q. In an isothermal change of an ideal gas,

Δ U = 0

. The change in the heat energy

Δ

Q is equal to

Q. Let Q and W denote the amount of heat given to an ideal gas and the work done by it in an isothermal process.
(a) Q = 0
(b) W = 0
(c) Q ≠ W
(d) Q = W

Q. An ideal gas expands isothermally from volume

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V_{2}

and is then compressed to original volume

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. The total work done by gas during the whole process is

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Q. For isothermal process, if heat added is

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Column-1 represents the process
Column-2 represents the $Δ U$ for that process and
Column-3 represents the work done expression for that process.
$\begin{matrix} C o l u m n I & C o l u m n 2 & C o l u m n 3 (I) & A d i a b a t i c e x p a n s i o n & (i) & 0 & (P) & w = q (I I) & I r r e v e r s i b l e i s o t h e r m a l c o m p r e s s i o n & (i i) & P o s i t i v e & (Q) & w = - q (I I I) & R e v e r s i b l e i s o t h e r m a l c o m p r e s s i o n & (i i i) & N e g a t i v e & (R) & w = 0 (I V) & F r e e e x p a n s i o n & (i v) & q & (S) & w = Δ U \end{matrix}$
A gas kept in a 100 L container was allowed to expand in a 5L evacuated container. Which set correctly describes this process?

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If in isothermal process Δ w work is done by gas,then choose incorrect

The correct option is D ΔP=0In isothermal process, ΔT=0 ( Temperature change is zero) and internal energy U=0 ,since it is a function of temperature.ΔS=ΔQT⇒ΔS≠0Hence, D is the incorrect option. i.e. ΔP=0

If in isothermal process $Δ$ w work is done by gas,then choose incorrect

The correct option is D $Δ P = 0$
In isothermal process, $Δ T = 0$ ( Temperature change is zero) and internal energy $U = 0$ ,since it is a function of temperature.
$Δ S = \frac{Δ Q}{T} \Rightarrow Δ S \neq 0$

Hence, $D$ is the incorrect option. i.e. $Δ P = 0$