Question

If in nature there may not be an element for which the principal quantum number n > 4, then the total possible number of elements will be

• A. 60
• B. 32
• C. 4
• D. 64

Answer 1

The correct option is A 60

For n = 1, maximum number of states $=2n^2=2$ and for n = 2, 3, 4, maximum number of states would be 8, 18, 32 respectively, Hence number of possible elements
= 2 + 8 + 18 + 32 = 60.